0=2+24.5t-4.9t^2

Solution for 0=2+24.5t-4.9t^2 equation:

0=2+24.5t-4.9t^2

We move all terms to the left:

0-(2+24.5t-4.9t^2)=0

We add all the numbers together, and all the variables

-(2+24.5t-4.9t^2)=0

We get rid of parentheses

4.9t^2-24.5t-2=0

a = 4.9; b = -24.5; c = -2;
Δ = b2-4ac
Δ = -24.52-4·4.9·(-2)
Δ = 639.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.5)-\sqrt{639.45}}{2*4.9}=\frac{24.5-\sqrt{639.45}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.5)+\sqrt{639.45}}{2*4.9}=\frac{24.5+\sqrt{639.45}}{9.8}
$